一道简单的指数函数应用题,求解! 在线等,急!

2025-03-04 05:46:38
推荐回答(1个)
回答1:

P5/P0=e^-5k=0.9
-5k=ln0.9
-k=1/5ln0.9
P=P0e^(1/5ln0.9*t)
P10/P0=e^(1/5ln0.9*10)=e^(2ln0.9)=e^ln0.81=0.81=81%

P/Po=e^(1/5ln0.9*t)=1/2
1/5ln0.9*t=ln0.5
t=5ln0.5/ln0.9=5*0.6931/0.1053=32.89,
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