∫(0,1)f(x)dx=∫(0,1) [x+2∫(0,1) f(t)dt]dx=x^2/2+2x∫(0,1) f(t)dt |(0,1)=1/2+2∫(0,1) f(t)dt所以∫(0,1) f(x)dx=-1/2所以f(x)=x+2∫(0,1) f(t)dt=x-2*(-1/2)=x+1
