请高数大神不吝赐教!

2025-04-27 19:34:41
推荐回答(1个)
回答1:



dy/dx=(2t⁵)'/(t⁶)'=(10t⁴)/(6t⁵)=5/(3t)

d²y/dx²=[d(dy/dx)/dt]/(dx/dt)

=[5/(3t)]'/(6t⁵)

=-5/(18t⁷)

d³y/dx³=[d(d²y/dx²)/dt]/(dx/dt)

=[-5/(18t⁷)]'/(6t⁵)

=[5/(126t⁸)]/(6t⁵)

=(5/756)t⁻¹³