若 0<β<α< π 2 且 cos(α+β)= 4 5 ,sin(α-β)= 5 13 ,那么cos2

2025-02-23 18:18:26
推荐回答(1个)
回答1:

0<β<α<
π
2

∴0<α+β<π,-
π
2
<α-β<
π
2

cos(α+β)=
4
5
,sin(α-β)=
5
13

sin(α+β)=
3
5
,cos(α-β)=
12
13

则cos2α=cos[(α+β)+(α-β)]
=cos(α+β)cos(α-β)-sin(α+β)sin(α-β)
=
4
5
×
12
13
-
3
5
×
5
13

=
33
65

故答案为:
33
65