(1)∵A1D⊥面ABC,∴A1D⊥BC∵AC⊥BC,A1D∩AC=D,∴BC⊥面ACC1A1∴A1B在面ACC1A1上的射影是A1C易证AC1⊥A1C,∴AC1⊥A1B(2)V四棱锥A1-BCC1B1=V棱柱ABCA1B1C1-V三棱锥A1-ABC=2V三棱锥A1-ABCS△ABC=1/2*AC*BC=2AD=1,AA1=2,勾股定理得A1D=√3∴V四棱锥A1-BB1C1C=2/3*S△ABC*A1D=4√3/3
这种东西二十块钱太少了
稍等