∵y=(x-2)分之根号(x²-4)+ 根号(4-x²)+ 1∴x²-4≥0 4-x²≥0 x≠2∴x=-2y=(-2-2)分之根号0+根号0+1y=1∴3x+4y=3x(-2)+4x1=-6+4=-2