1^5+2^5+3^5+4^5+5^5+…+n^5=?并用非反证法证明下,谢啦

2025-03-09 10:29:02
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回答1:

sn=5^1+5^2+5^3+...+5^n,5sn=5^2+5^3+5^4+...+5^n+5^(n+1),5sn-sn=5^(n+1)-5^1,sn=[5^(n+1)-5]/4.反证法很简单…