一列数:1⼀2,1⼀6,1⼀12,1⼀20,1⼀30,1⼀42........用简便算法计算这列数前2005项的和

2025-03-10 22:51:44
推荐回答(1个)
回答1:

对任意的正整数n都有1/n(n+1)=1/n-1/(n+1)

1/2+1/6+……+1/(2005*2006)
=(1-1/2)+(1/2-1/3)+……+(1/2005-1/2006)
=1-1/2006
=2005/2006