ln[(1+1/n^2)*(1+2/n^2)*(1+3/n^2)*(1+4/n^2)……(1+n/n^2)]
=ln(1+1/n^2)+ln(1+2/n^2)+ln(1+3/n^2)+ln(1+4/n^2)+……+ln(1+n/n^2)
=(1/n^2)ln{(1+1/n^2)^(n^2)}+(2/n^2)ln{[1+1/(n^2/2)]^(n^2/2)}+……+(n/n^2)ln{[1+1/(n^2/n)]^(n^2/n)}(n->∞)
=1/n^2+2/n^2+……n/n^2(n->∞)
=n(n+1)/(2n^2)(n->∞)
=1/2
∴原式=e^(1/2)=√e