x³+2x²-3x=x(x²+2x-3)=x(x+3)(x-1)=0,解得x1=0,x2=-3,x3=1
x（x²+2x-3）=0 x=0或x²+2x-3=0将x²+2x-3=0的解求出即可 有三个答案
x(x^2+2x-3)=0x(x-1)(x+3)=0x=0或1或-3
x(x2+2x-3)=0x(x-1)(x+3)=0x=0或x=1或x=-3
