不定积分计算题6小题,三角函数类型的

2025-03-04 12:49:16
推荐回答(1个)
回答1:

∫dx/sin2x+2sinx
=∫dx/2sinx(cosx+1)
=∫dx/8sin(x/2)cos(x/2){cox(x/2)}^2
=1/4∫1/sin(x/2)cos(x/2)dtan(x/2)
=1/4∫(cos(x/2)/sin(x/2)+sin(x/2)/cos(x/2)dtan(x/2)
=1/4∫1/tan(x/2)dtan(x/2)+1/4∫tan(x/2)dtan(x/2)
=1/4ln绝对值tan(x/2)+1/8{tan(x/2)}^2+C