编写程序：计算π的近似值，π的计算公式为

#include 

main() 

{ int n,i; double t,

sum;/*1*/ 

printf("请输入n的值\n"); 

scanf("%d",&n); 

sum=2; i=1; t=2;/*2*/ 

while(i

/*3*/ // sum=sum*t; i=i+1; } 

printf("π的值=%f\n",t);/*4*/ }

或。

写一个Java程序来实现蒙特卡洛法求π的近似值：

import java.io.BufferedReader;

import java.io.InputStreamReader;

public class MonteCarloPi {

public static void main(String[] args) throws Exception{

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

System.out.print("How many darts shoud I toss at the board?\n");

String s = br.readLine();

int numberOfDarts = Integer.parseInt(s.trim());

double radius = 1.0;

Dartboard d = new Dartboard(radius);

for(int i=1; i<=numberOfDarts; i++){

Toss t = Toss.getRandom(radius);

d.strike(t);

}

double fractionIn = d.getFractionIn();

double pi = 4.0 * fractionIn;

System.out.println("Pi is approximately "+pi);

}

}

 class Dartboard{

private double radius;

private int insideCircle, outsideCircle;

public Dartboard(double radius){

this.radius = radius;

insideCircle = 0;

outsideCircle = 0;

}

public void strike(Toss toss){

double x = toss.getX();

double y = toss.getY();

if(Math.sqrt(x*x + y*y) < radius)

insideCircle++;

else

outsideCircle++;

}

public double getFractionIn() {

double total = (double) (insideCircle + outsideCircle);

return (double) insideCircle/total;

}

}

class Toss{

private double x,y;

public Toss(double x, double y){

this.x = x;

this.y = y;

}

public double getX(){return x;}

public double getY(){return y;}

public static Toss getRandom(double radius){

double x,y;

double size = Math.random();

double sign = Math.random();

size = size * radius;

if(sign > 0.5)

x = size;

else

x = -size;

size = Math.random();

sign = Math.random();

size = size * radius;

if(sign > 0.5)

y = size;

else

y = -size;

return new Toss(x,y);

}

}

扩展资料：

C语言:用循环结构分别编写程序

#include

void main()

{

\x09int n=1;

\x09float temp;

\x09float sum=0;

\x09do

\x09{

\x09\x09temp=(float)1/(2*n-1);

\x09\x09if(n%2==1)

\x09\x09\x09sum+=temp;

\x09\x09else

\x09\x09\x09sum-=temp;

\x09\x09n++;

\x09}while(temp>=0.000001);

\x09printf("Pi=%f\n",sum*4);

}

公式没有问题，每项到最后会趋向1的，但是你的代码里错了好几处!现在这个代码运行没有问题了，你看看: #includemain()
{
int n,i;
float sum;
printf("请输入n的值\n");
scanf("%d",&n);
sum=2;
i=1;
while(i { // 你的t是没有用的，而且你用了int肯定完蛋了，另外注意除法!!!
sum=sum*(2*i)*(2*i)/(2*i-1)/(2*i+1); i=i+1;
}
printf("π的值=%f\n",sum);
}

这个公式有问题啊，我怎么看是非收敛的啊？越来越大啊