已知3x-4y=0,求分式x^2+2xy⼀3x^2-y^2的值

2025-04-26 17:23:06
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回答1:

解:3x-4y=0
x=4/3y
原式=(x^2+2xy)/(3x^2-y^2)
=(16/9y^2+8/3y^2)/(16/3y^2-y^2)
=(40/9y^2)/(13/3y^2)
=40/39