f(x)定义域x>-1且x≠0f(x)=1/[(x+1)ln(x+1)]f`(x)=-[(x+1)ln(x+1)]`/[(x+1)ln(x+1)]^2 =-[ln(x+1)+1]/[(x+1)ln(x+1)]^2分母[(x+1)ln(x+1)]^2>0只需讨论-[ln(x+1)+1]的正负当-[ln(x+1)+1]≥0时-1此时f`(x)≥0当-[ln(x+1)+1]<0时x>1/e-1此时f`(x)<0∴f(x)的增区间(-1,1/e-1] 减区间[1/e-1,+∞)