三角函数tan(a+b)=tana+tanb⼀1-tana*tanb的推导过程!

2025-05-05 17:40:44
推荐回答(1个)
回答1:

tan(A+B)
=sin(A+B)/cos(A+B)
=(sinAcosB+sinBcosA)/(cosAcosB-sinAsinB)
分子,分母同时除以cosAcosB得:
=(sinA/cosA+sinB/cosB)/(1-sinAsinB/cosAcosB)
=(tanA+tanB)/(1-tanAtanB)