磷酸一氢钠c1 +磷酸二氢钠c2 在水溶液中的质子条件式怎么写,麻烦详

2025-03-17 17:08:52
推荐回答(4个)
回答1:

所采用的试剂和仪器:AR磷酸(85%计),AR无水碳酸钠(99.8%),备用试剂1mol/LNaOH溶液和1mol/LH3PO4,精密PH试纸或PH计,铁架台,酒精灯,蒸发皿
1.磷酸二氢钠的制备:(纯碱中和法)步骤:称取82g85%磷酸,36g碳酸钠;而后分别50ml水中(碳酸钠用热水);在不断搅拌下缓慢的加入碳酸钠溶液进行中和反应,生成磷酸二氢钠溶液,此时测溶液PH值,要求大约在
4。如果偏酸,则需要加入NaOH进行中和,偏碱加入适当的磷酸。调整好PH后,放在蒸发皿上进行加热蒸发浓缩,冷却到60-70度时,吸出结晶,并得到二水磷酸二氢钠。如果继续蒸干,则得到无水磷酸二氢钠。2.磷酸氢二钠的制备:步骤:称取36g85%磷酸,36gNa2CO3;而后分别50ml水中(碳酸钠用热水);在不断搅拌的情况下缓慢的加入纯碱溶液进行中和反应,使反应液PH值为8.4-8.6,过酸或过碱都需要加氢氧化钠或磷酸进行调整。而后进行蒸发,待有少量晶体析出时停止蒸发,冷却到室温25度,此时有大量十二水磷酸氢二钠晶体析出。另外,将制备好的十二水磷酸氢二钠晶体于34度下小心干燥,即得到二水磷酸氢二钠产品。

回答2:

NaH2PO4:
[H+]+[H3PO4]=[OH-]+[HPO42-]+2[PO43-]
Na2HPO4:
[H+]+[H2PO4-]+2[H3PO4]=[OH-]+[PO43-]

回答3:

质子守恒即利用“得质子=失质子”建立等式。

得:水得H+为H3O+

H2PO4-得一个H+为 H3PO4

失:

水失H+得OH-

H2PO4-失一个H+为HPO4 2-失两个为PO4 3-

则有

c(H3O+)+c(H3PO4)=c(OH-)+c(HPO4 2-) +2*c(PO4 3- )

回答4:

[PO4 3-]+[OH-]=[H2PO4 -]+2[H3PO4]+[H+]-c2

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