一道数学代数题。题目如下图: (20分哦!)

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2025-03-05 09:52:18
推荐回答(1个)
回答1:

x^2 - 3x +1 = 0
同除以x
x - 3 + 1/x = 0
x + 1/x = 3

(x+1/x)^2 = x^2 + (1/x)^2 + 2
(x-1/x)^2 = x^2 + (1/x)^2 - 2 = (x+1/x)^2 - 4 = 9 - 4 = 5

故原式 = 根号5