已知x=√3+√2⼀√3-√2,Y=√3-√2⼀√3+√2,求代数式3x-5xy+3y的值

2025-02-25 18:13:57
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回答1:

x=√3+√2/√3-√2 =(√3+√2)^2/(√3-√2)(√3+√2) =5+2√6 y=(√3-√2)/(√3+√2) =(√3-√2)^2/(√3+√2)(√3-√2) =5-2√6 3x-5xy+3y =3(x-y)^2+xy =3(5+2√6-5+2√6)^2+(5+2√6)(5-2√6) =3*96+1 =289

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