2(x-3)²=x(x-3)2(x-3)(x-3)-x(x-3)=0(2x-6-x)(x-3)=0(x-6)(x-3)=0x1=6 x2=3(x²-1)²-5(x²-1)+4=0(x²-1-4)(x²-1-1)=0x1=正负根号5 X2=正负根号2(3x-4)²=(4x-3)²(3x-4)²-(4x-3)²=0(3x-4+4x-3)(3x-4-4x+3)=0(7x-7)(-x-1)=07(x-1)(x+1)=0x1=1 x2=-1