第十题怎么做啊?

2025-04-23 13:58:22
推荐回答(1个)
回答1:

=lim(x²-sin²x)/x²sin²x
=lim(x+sinx)/x*lim(x-sinx)/x³
=lim(1+sinx/x)*limsinx/6x
=2*1/6
=1/3