求一个没错误的银行家算法程序，c语言或C++的都行！！！！

#include
#include
#include
#include/*用到了getch()*/
#defineM5/*进程数*/
#defineN3/*资源数*/
#defineFALSE0
#defineTRUE1
/*M个进程对N类资源最大资源需求量*/
intMAX[M][N]={{7,5,3},{3,2,2},{9,0,2},{2,2,2},{4,3,3}};
/*系统可用资源数*/
intAVAILABLE[N]={10,5,7};
/*M个进程已分配到的N类数量*/
intALLOCATION[M][N]={{0,0,0},{0,0,0},{0,0,0},{0,0,0},{0,0,0}};
/*M个进程已经得到N类资源的资源量*/
intNEED[M][N]={{7,5,3},{3,2,2},{9,0,2},{2,2,2},{4,3,3}};
/*M个进程还需要N类资源的资源量*/
intRequest[N]={0,0,0};
voidmain()
{
inti=0,j=0;
charflag;
voidshowdata();
voidchangdata(int);
voidrstordata(int);
intchkerr(int);
showdata();
enter:
{
printf("请输入需申请资源的进程号（从0到");
printf("%d",M-1);
printf("）:");
scanf("%d",&i);
}
if(i<0||i>=M)
{
printf("输入的进程号不存在，重新输入!\n");
gotoenter;
}
err:
{
printf("请输入进程");
printf("%d",i);
printf("申请的资源数\n");
printf("类别:ABC\n");
printf("");
for(j=0;j{
scanf("%d",&Request[j]);
if(Request[j]>NEED[i][j])
{
printf("%d",i);
printf("号进程");
printf("申请的资源数>进程");
printf("%d",i);
printf("还需要");
printf("%d",j);
printf("类资源的资源量!申请不合理，出错!请重新选择!\n");
gotoerr;
}
else
{
if(Request[j]>AVAILABLE[j])
{
printf("进程");
printf("%d",i);
printf("申请的资源数大于系统可用");
printf("%d",j);
printf("类资源的资源量!申请不合理，出错!请重新选择!\n");
gotoerr;
}
}
}
}
changdata(i);
if(chkerr(i))
{
rstordata(i);
showdata();
}
else
showdata();
printf("\n");
printf("按'y'或'Y'键继续,否则退出\n");
flag=getch();
if(flag=='y'||flag=='Y')
{
gotoenter;
}
else
{
exit(0);
}
}
/*显示数组*/
voidshowdata()
{
inti,j;
printf("系统可用资源向量:\n");
printf("***Available***\n");
printf("资源类别:ABC\n");
printf("资源数目:");
for(j=0;j{
printf("%d",AVAILABLE[j]);
}
printf("\n");
printf("\n");
printf("各进程还需要的资源量:\n");
printf("******Need******\n");
printf("资源类别:ABC\n");
for(i=0;i{
printf("");
printf("%d",i);
printf("号进程:");
for(j=0;j{
printf("%d",NEED[i][j]);
}
printf("\n");
}
printf("\n");
printf("各进程已经得到的资源量:\n");
printf("***Allocation***\n");
printf("资源类别:ABC\n");
for(i=0;i{
printf("");
printf("%d",i);
printf("号进程:");
/*printf(":\n");*/
for(j=0;j{
printf("%d",ALLOCATION[i][j]);
}
printf("\n");
}
printf("\n");
}
/*系统对进程请求响应，资源向量改变*/
voidchangdata(intk)
{
intj;
for(j=0;j{
AVAILABLE[j]=AVAILABLE[j]-Request[j];
ALLOCATION[k][j]=ALLOCATION[k][j]+Request[j];
NEED[k][j]=NEED[k][j]-Request[j];
}
}
/*资源向量改变*/
voidrstordata(intk)
{
intj;
for(j=0;j{
AVAILABLE[j]=AVAILABLE[j]+Request[j];
ALLOCATION[k][j]=ALLOCATION[k][j]-Request[j];
NEED[k][j]=NEED[k][j]+Request[j];
}
}
/*安全性检查函数*/
intchkerr(ints)
{
intWORK,FINISH[M],temp[M];
inti,j,k=0;
for(i=0;ifor(j=0;j{
WORK=AVAILABLE[j];
i=s;
while(i{
if(FINISH[i]==FALSE&&NEED[i][j]<=WORK)
{
WORK=WORK+ALLOCATION[i][j];
FINISH[i]=TRUE;
temp[k]=i;
k++;
i=0;
}
else
{
i++;
}
}
for(i=0;iif(FINISH[i]==FALSE)
{
printf("\n");
printf("系统不安全!本次资源申请不成功!\n");
printf("\n");
return1;
}
}
printf("\n");
printf("经安全性检查，系统安全，本次分配成功。\n");
printf("\n");
printf("本次安全序列：\n");
printf("进程依次为");
for(i=0;i{
printf("%d",temp[i]);
printf("->");
}
printf("\n");
return0;
}