(1)∵tan(α+
)=π 4
=3,tanα+1 1?tanα
∴tanα=
;1 2
(2)∵tanα=
,1 2
∴sin2α=2sinαcosα=
=2sinαcosα sin2α+cos2α
=2tanα 1+tan2α
;4 5
∵α为第三象限角,tanα=
,1 2
∴cosα=-
=-
1 1+tan2α
,sinα=-2
5
5
=-
1?cos2α
,
5
5
则cos(α+
)=π 6
cosα-
3
2
sinα=1 2
×(-
3
2
)-2
5
5
×(-1 2
)=
5
5
.
?2
5
1
10