求e^x-e^y=sin(xy)的导数dy⼀dx

2025-03-05 05:20:21
推荐回答(1个)
回答1:

两边同时对x求导
e^x-e^yy'=cos(xy)(y+xy')
y'=[e^x-ycos(xy)]/【xcos(xy)+e^y】
dy/dx=[e^x-ycos(xy)]/【xcos(xy)+e^y】