怎样把txt转化为二进制文本格式

2025-02-27 15:19:15
推荐回答(1个)
回答1:

  dfm文件二进制格式时, 其文件会加一个文件头, 其中前3个字节来标识其为二进制, 这三个字节分别为:$FF, $0A, $00. 因为这三个字节在文本类型的文件中是不可能存在的,所以可以判断这3个字节就可以了.
  function IsBinDfm(const ADfmFileName: string): Boolean;  Var   mBinStream:TMemoryStream;
   mBuff : array [0..2] of byte;  begin   mBinStream := TMemoryStream.Create;   try   mBinStream.LoadFromFile(ADfmFileName);
   mBinStream.Read(mBuff, 3);
   //前三字节: $FF, $0A, $00
   if (mBuff[0] = $FF) and (mBuff[1] = $0A) and (mBuff[2]= $00) then
   Result := True   else   Result := False;
   finally
   mBinStream.Free;   end;  end;  判断出来后, 再将二进制转为文本格式就容易了.Delphi提供了ObjectResourceToText函数.写法如下:
  procedure DfmBin2Txt(ADfmFileName: string);  Var   inFileStream: TMemoryStream;
   outFileStream: TFileStream;  begin   inFileStream := TMemoryStream.Create;
   inFileStream.LoadFromFile(ADfmFileName);   try   outFileStream := TFileStream.Create(ADfmFileName, fmCreate);   try   try   inFileStream.Seek(0, soFromBeginning);
   ObjectResourceToText(inFileStream, outFileStream);
   except
   Raise Exception.Create('This dfm is bin, error on trans bin to txt.');   end;   finally
   inFileStream.Free;   end;  end;  至此,大功告成!