已知数列{an}的前n项和Sn=n^2-9n,第k项满足5<ak<8,则k等于

2025-02-25 00:44:51
推荐回答(1个)
回答1:

Sn=n^2-9n
S(n-1)=(n-1)^2-9(n-1)
=n^2-2n+1-9n+9
=n^2-11n+10

an=Sn-S(n-1)
=n^2-9n-(n^2-11n+10)
=n^2-9n-n^2+11n-10
=2n-10

ak=2k-10
5<ak<8
5<2k-10<8
15<2k<18
7.5<k<9

所以k=8