(2的二次方+1)(2的四次方+1)(2的八次方+1)……(2的三十二方+1)

2025-02-22 12:11:54
推荐回答(2个)
回答1:

(2^2+1)(2^4+1)(2^8+1)×...×(2^32+1)
=(2^-1)(2^2+1)(2^4+1)(2^8+1)×...×(2^32+1)×1/3
=(2^4-1)(2^4+1)(2^8+1)×...×(2^32+1)×1/3
=(2^8-1)(2^8+1)×...×(2^32+1)×1/3
.......
=(2^64-1)/3.
方法用平方差公式:(a+1)(a-1)=a²-1,

回答2:

5,17,257,65537,4294967297