用换元法解分式方程x^2⼀(x-1)+(x-1)⼀x^2-2=0时,如果设x^2⼀(x-1)=y,

2025-03-10 21:59:37
推荐回答(1个)
回答1:

化为:
y+1/y-2=0
y²+1-2y=0
(y-1)²=0
y=1