求不定积分∫cos^3xdx

2025-03-09 20:00:32
推荐回答(1个)
回答1:

答:

∫ (cosx)^3 dx
=∫ (cosx)^2 d(sinx)
=∫ 1-(sinx)^2 d(sinx)
=sinx-(1/3)*(sinx)^3+C