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13问答网 > 化简下面三角函数 Asin(2πt)+B(sin3πt)

化简下面三角函数 Asin(2πt)+B(sin3πt)

将下面两个三角函数化简成一个三角函数，谢谢

2025-03-15 20:38:15

推荐回答（1个）

回答1：

5sin2πt+10sin3πt
= 10sinπtcosπt+10[3sinπt-4(sinπt)^3]
= 10sinπt{3-4(sinπt)^2±√[1-(sinπt)^2]}

Asin2πt+Bsin3πt
= 2Asinπtcosπt+B[3sinπt-4(sinπt)^3]
= sinπt{3B-4B(sinπt)^2±2A√[1-(sinπt)^2]}

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