含碳52%,含氢13%,含氧35%那么CHO的物质的量只比为52%/12:13%/1:35%/16=2:6:1即该醇为C2H6OC2H6O+6H2O2===2CO2+9H2O462041kg90%x解得x=4.93kg如果还有疑问百度HI找我详谈