8又7⼀10-8又11⼀20+2又11⼀12等于多少脱式计算?

2025-03-07 02:58:08
推荐回答(1个)
回答1:

原式=8+7/10-8-11/20+2+11/12
=8-8+2+7/10-11/20+11/12
=2+(14/20-11/20)+11/12
=2+3/20+11/12
=2+9/60+55/60
=2+64/60
=2+16/15
=3又1/15