写出Na2HPO4水溶液的质子平衡式

2025-03-10 23:12:08
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回答1:

Na2HPO4
电荷守恒,[Na+]+[H+]=[OH-]+[H2PO4-]+2[(HPO4)2-]+3[(PO4)3-]
物料守恒,[Na+]=2[(PO4)3-]+2[(HPO4)2-]+2[H2PO4-]+2[H3PO4]
质子守恒,[OH-]+[(PO4)3-]=[H2PO4-]+2[H3PO4]+[H+]