一道物理化学题公式,请教老师指点一下,,谢谢老师了!!

2025-04-27 20:11:05
推荐回答(1个)
回答1:

P1*V1=nRT
P2*V2=nRT
P1*V1=P2*V2

P1=0.5MPa
P2=0.1MPa
(P2=0.2P1)
V2=5V1
因为恒外压(外压为0.1MPA)膨胀过程,做负功,求做功得用恒外压P2
W=-P2*(V2-V1)= -P2*4V1 = -0.2P1*4V1 = -0.8P1*V1 = -0.8*nRT = -0.8*1*8.314*300 = -1995.36