4. sin(y) =0 ,when y = 2*k*pi , k= 0,1,2,....
=> 4X+5 = 2*k*pi
=> X = ( 2*k*pi -5) /4 , k= 0,1,2,....
the end
5. ln(y) exist when y > 0
=> x / sin (x) > 0
1. x >0 and sin(x)>0
=> 2*k*pi < x < pi+2*k*pi k= 0,1,2,....
2.. x < 0 and sin(x) <0
=> -pi-2*k*pi < x < - 2*k*pi k= 0,1,2,....
在1 或2的范围内 the ends
内容全部来源于网络收集，如有侵权，请联系网站删除：QQ：24596024