请问下面这道高数题如何做?请写出详细解答

2025-05-05 08:53:51
推荐回答(1个)
回答1:

交换积分次序
原式=∫y²dy∫sin(xy)dx (0≤y≤1,-√(1-y²)≤x≤√(1-y²))
=∫y[-cosy√(1-y²+cosy√(1-y²+]dy (0≤y≤1)
=∫0dy (0≤y≤1)
=0