高一数学题

2025-03-13 01:33:48
推荐回答(1个)
回答1:

(1)f(x)ax+1>0,ax>-1,a>0,x>-1/a①
x>0,②①②之交为②。
(ax+1)/x<(a-4)x+2a-5,③

由②③,ax+1<(a-4)x^2+(2a-5)x,
整理得(a-4)x^2+(a-5)x-1>0,
(x-1)[(a-4)x+1]>0,
a=4时x>1;a>4时x>1或x<-1/(a-4);0与②求交集得a>=4时x>1;0