急急急。。。数学求导数题(x+(x+x^1⼀2)^1⼀2)1⼀2) 真的不会啊,麻烦数学好的帮帮忙!!

比较急,答对加分!!!
2025-02-24 15:49:37
推荐回答(4个)
回答1:

用求复合函数导数的法则:
设y=[x+(x+x^1/2)^1/2]^1/2,
则y'=1/{2[x+(x+x^1/2)^1/2]^1/2}*{1+1/[2(x+x^1/2)^1/2]*[1+1/(2x^1/2)]}
=1/{2[x+(x+x^1/2)^1/2]^1/2}*{1+[2x^1/2+1]/[4x^1/2*(x+x^1/2)]}
=[4x^1/2*(x+x^1/2)+2x^1/2+1]/{8x^1/2*(x+x^1/2)*[x+(x+x^1/2)^1/2]^1/2}.

回答2:

f’(x)=0.5(x+(x+x^0.5)^0.5)^(-0.5)*(1+0.5(x+x^0.5)^(-0.5))*(1+0.5x^(-0.5))

回答3:

0.5*(x+(x+x^0.5)^0.5)^(-0.5)*(1+(1+0.5x^(-0.5))*(0.5*(x+x^0.5)^(-0.5)))

回答4:

1啊