2XY⼀X^2-y^2-y⼀y-x+x⼀x+y

8年级分式部分计算题
2025-04-04 13:57:36
推荐回答(1个)
回答1:

原式=2xy/(x^2-y^2)+y/(y-x)+x/(x+y)
=2xy/(x+y)(x-y)+y(x+y)/(x+y)(x-y)+x(x-y)/(x+y)(x-y)
=2xy+xy+y^2+x^2-xy/(x+y)(x-y)
=(x+y)^2/(x+y)(x-y)
=(x+y)/(x-y)