(1)n(O2)=
=0.006mol,0.1344L 22.4L/mol
一份中:n(CaO2?nH2O)=2n(O2)=0.012mol,
n(CaCO3)=
=0.014mol,1.40g 100g/mol
n(CaO)=n(CaCO3)-n(CaO2?nH2O)=0.002mol,
2.168 g样品中m(CaO)=0.002mol×56g/mol×2=0.224g,
答:2.168g样品中CaO的质量为0.224g,
(2)2.168g过氧化钙样品中的质量为2.168g-0.224g,
则2×0.012×(72+18n)=2.168-0.224,
n=0.5,
答:样品中CaO2?nH2O的n值为0.5.