(√3-√2)*(√2-1)/(√3-1)=(√3-√2)*(√3+1)*(√2-1)/[(√3-1)(√3+1)]=(3+√3-√6-√2)*(√2-1)/2=(3+√3-√6-√2)*(√2-1)/2=(3√2-3+√6-√3-2√3+√6-2+√2)/2=(4√2-5+2√6-3√3)/2
