已知α属于(π⼀2,π),且4sinα=-3cosα,求cos(α+π⼀4)⼀sin2α

2025-02-24 00:59:37
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回答1:

tanα=-3/4
cosα<0, (cosα)^2=1/(1+(tanα)^2)=16/25
cosα=-4/5
sinα=3/5
cos(α+π/4)=cosαcos(π/4)-sinαsin(π/4)=-7√2/10
sin2α=2sinαcosα=-24/25
cos(α+π/4)/sin2α=35√2/48