设随机变量X1,X2,…,Xn(n>1)独立同分布,且方差σ2>0.令随机变量Y=1nni=1Xi,则(  )A.D(X1+

2025-04-14 04:22:34
推荐回答(1个)
回答1:


由于随机变量X1,X2,…,Xn(n>1)独立同分布,
于是可得:
COV(X,Y)=COV(X1

1
n
n
/picurl?url=https%3A%2F%2Fiknow-pic.cdn.bcebos.com%2F203fb80e7bec54e754c734a9ba389b504fc26a59%3Fx-bce-process%3Dimage%2Fquality%2Cq_85
i=1
Xi)=
1
n
COV(X1
n
/picurl?url=https%3A%2F%2Fiknow-pic.cdn.bcebos.com%2F203fb80e7bec54e754c734a9ba389b504fc26a59%3Fx-bce-process%3Dimage%2Fquality%2Cq_85
i=1
Xi)
=
1
n
n
/picurl?url=https%3A%2F%2Fiknow-pic.cdn.bcebos.com%2F203fb80e7bec54e754c734a9ba389b504fc26a59%3Fx-bce-process%3Dimage%2Fquality%2Cq_85
i=1
COV(X1Xi)

=
1
n
COV(X1X1)
=
1
n
D(X1)
=
1
n
σ2

故答案选:C.