已知f(x-1⼀x)=x^2+1⼀x^2,求f(x)解析式?

2025-01-05 15:41:53
推荐回答(2个)
回答1:

f(x-1/x)=x^2+1/x^2=(x-1/x)²+2
设x-1/x=t
则f(t)=t²+2
所以f(x)=x²+2

回答2:

A-B=(cosa-cosb,
sina-sinb)|A-B|^2=(cosa-cosb)^2+(sina-sinb)^2=2-2(cosacosb+sinasinb)=4/5cosacosb+sinasinb=3/5cos(a-b)=cosacosb+sinasinb=3/5-π/2