设f(x)={[(x^2-x)⼀(x-1)](当x≠1), 2(当x=1)},求x→1时lim f(x)的极限。

2024-11-22 00:55:54
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回答1:

解:lim(x->1)[(x²-1)/(x-1)]=lim(x->1)[(x+1)(x-1)/(x-1)] (分解因式)
=lim(x->1)[x(x-1)/(x-1)] (分子分母同除(x-1))
=lim(x->1)x (分子分母同除(x-1))
=1