SELECT *
FROM CourseScore
WHERE Course = '数学'
AND Score > (
SELECT AVG(Score)
FROM CourseScore
WHERE Course = '数学'
)
更通用一些的:
SELECT A.*
FROM CourseScore A
JOIN (--查询各科目的平均成绩
SELECT Course, AVG(Score) Average
FROM CourseScore
GROUP BY Course
) B ON A.Course = B.Course
WHERE A.Course = B.Course
AND A.Score > B.Average
ORDER BY A.Course, A.Score DESC --按科目、成绩(倒序)
满足要求吗?