用0~4这五个数字可以组成多少个无重复数字的三位数 求详细过程 谢谢

用排列的方法 谢谢
2025-03-04 18:14:17
推荐回答(2个)
回答1:

百位数可有4种选择;十位有4种选择;个位数有3种选择。
一共可组成4*4*3=48个三位数。

回答2:

100 .200.300.400.500
110.220.330.440.550
102.103.104.105.101
201.202.203.204.205
301.302.303.304.305
401.402.403.404.405
501.502.503.504.505
123.124.125.213..214.215. 312.313.314.315
412.413.414.415.411.410.210.310.510.
521.523.524.543.542.541.545.
120.130.140.150
210.220230.240.250
310.320.330.340.350
410.420.430.450.440
能想到的就这些了