按抛物线的定义，P与准线的距离等于与焦点F(p/2, 0)的距离, PO = PF, 即P为以OF为底的等腰三角形的顶点，P到OF的垂线平方OF，所以OF=P的横坐标的2倍，即p/2 = 1, p = 2
y² = 4x
bx²+9y² = 9b
x²/9 + y²/b = 1
c² = 1 = 9 - b
b = 8
x²/9 + y²/8 = 1
A, B在y轴右侧,
x²/9 + 4x/8 = 1
x = 3/2 (舍去x = -6 < 0)
y = ±√6
渐近线的斜率 = ±√6/(3/2) = ±2√6/3
渐近线: y = ±(2√6/3)x
b/a = 2√6/3, b² = 8a²/3
x²/a² - y²/(8a²/3) = 1
根据对称性,不妨设P在x轴上方, m > 0
y² = 4*1/2 = 2, y = √2
P(1/2, √2)
过P: (1/2)²/a² - (√2)²/(8a²/3) = 1
无解,题似乎有问题
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