原式=√【(4-2√3)/2】=√【((√3)²-2√3+1²)/2】=√【(√3-1)²/2】=√(√3-1)²/√2=(√3-1)/√2=【√2(√3-1)】/(√2)²=(√6-√2)/2请采纳,O(∩_∩)O谢谢
√(2-√3)=√(3/2-√3+1/2)=√((√(3/2))²-2x√(3/2)x√(1/2)+(√(1/2))²)=√(√(3/2)-√(1/2))²=√(3/2)-√(1/2)=(√(6-√2))/2=(√3-1)x√2/2