当m为何值时,分式方程x⼀x 3-x 1⼀x-2=x-2m⼀m臿0藿5 x-6的解不小于一

2025-05-01 09:45:17
推荐回答(1个)
回答1:

x/(x+3) - (x+1)/(x-2) = (x-2m)/(x²+x-6)
两边同乘以x²+x-6
x(x-2) - (x+1)(x+3) = x-2m
x²-2x-(x²+4x+3) = x-2m
-2x-4x-3 = x-2m
2m = 7x+3
m=7/2x+3/2
x≥1,且x≠2
∴m=7/2x+3/2≥7/2+3/2=5,且m≠7/2*2+3/2=17/2
∴m≥5且m≠17/2