已知:如图,AB=AC,E是AC上任意一点,ED⊥BC,垂足为D,延长DE交BA的延长线于点F.求证AE=AF。急需!!!谢谢

2025-05-06 04:47:31
推荐回答(2个)
回答1:

∵AB=AC∴∠B=∠C.∵FD⊥BC,∴∠C﹢∠DEC=90° ∠B+∠F=90°∵∠DEC=∠AEF∴∠C+∠AEF=90°∵∠B=∠C∴∠F=∠AEF∴AE=AF
呵呵。。。怕你。。。所以废话了点。。。新号。。。多多照顾啊!

回答2:

∵ED⊥BC
∴∠FEA=∠DEC=90°-∠C,∠F=90°-∠B
∵AB=AC
∴∠B=∠C
∴∠AEF=∠F
∴AF=AE